Math, asked by Pogo8524, 1 year ago

If the three vertices of the parallelogram abcd are a (1, a), b(3, a), c(2, b), then d is equal to

Answers

Answered by suhaspranay
0
can be found by using distance formula
Answered by jatindchoudhari
0

Answer:

D=(0,b)

Step-by-step explanation:

ABCD is a parallelogram.

`AB || DC`, then slope of line `AB=` slope of line `DC (a-a)/(3-1)`

`=(b-y)/(2-x) implies y=b`

Also, `AD||BC, (a-y)/(1-x)=(a-b)/(3-2)`

`(a-b)/(1-x)=(a-b)/(3-2) implies (a-b)/(1-x) xx 1/(a-b)=1`

`1-x=1`

`x=0`

Then points D are (0, b)

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