If the three vertices of the parallelogram abcd are a (1, a), b(3, a), c(2, b), then d is equal to
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can be found by using distance formula
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Answer:
D=(0,b)
Step-by-step explanation:
ABCD is a parallelogram.
`AB || DC`, then slope of line `AB=` slope of line `DC (a-a)/(3-1)`
`=(b-y)/(2-x) implies y=b`
Also, `AD||BC, (a-y)/(1-x)=(a-b)/(3-2)`
`(a-b)/(1-x)=(a-b)/(3-2) implies (a-b)/(1-x) xx 1/(a-b)=1`
`1-x=1`
`x=0`
Then points D are (0, b)
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