if the Tm term of AP be 1/n and Tn term is 1/m,Show that its Tmn term is 1
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EXPLANATION.
- GIVEN
Tm = 1/n
Tn = 1/m
SHOW THAT Tmn = 1
Tm = a + ( m - 1 ) d = 1/n .....(1)
Tn = a + ( n - 1 ) d = 1/m .......(2)
from equation (1) and (2)
we get,
( m - n) d = (1/n - 1/m )
d = 1/nm
put the value of d = 1/nm in equation (1)
we get,
a + ( m - 1 )1/nm = 1/n
a + m / nm - 1/nm = 1/n
a = 1/nm
Therefore,
Tmn = a + ( mn - 1 ) d
1/nm + ( mn - 1) 1/nm
1/nm + mn / nm - 1/nm
Tmn = 1
Hence proved
NOTE = ALSO SEE THE ATTACHMENT OF THIS ANSWER.
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Step-by-step explanation:
tmn = a+(mn-1)d
1/nm + (mn-1)1/nm
1/nm + mn/nm- 1/nm
Cancel all
Answer is 1
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