If the total height of the silver solid is 19 cm and diameter of the cylinder is
7 cm, find the volume and cost of the silver solid at the rate of Rs. 400 per cubic cm.
Answers
Given :-
- Total height of the silver solid, H = 19 m.
- The radius of the hemispherical solids attached at the top and the bottom of the silver solid is 7m.
To Find :-
- Volume of the Silver solid and the cost if the rate is given to be ₹ 400 per m³
Solution :-
The silver solid is formed using two hemispheres and one cylinder.
So, The volume of the silver solid will be Volume of the two hemispheres and the cylinder.
⇒ Volume of Hemisphere = 2/3 πr³
But there are two hemispheres, So
⇒ Volume of 2 hemispheres = 4/3 πr³
⇒ Volume = 4/3 × 22/7 × 7 × 7 × 7
⇒ Volume = 88 × 7 × 7 / 3
⇒ Volume = 4312/3
⇒ Volume, V = 1437.33 m³
Now, Let us find the volume of the cylinder,
- Height of cylinder = Total height - 2×Radius of Hemisphere
- Radius of Cylinder = 7 m
Volume of Cylinder,
⇒ Volume, v = πr²h
⇒ Volume, v = 22/7 × 7 × 7 × (19 - 14)
⇒ Volume, v = 22 × 7 × 5
⇒ Volume, v = 770 m³
Now, The volume of the silver solid is,
⇒ Volume = V + v
⇒ Volume = 1437.33 + 770
⇒ Volume = 2207.33 m³
Furthermore, The cost can be calculated as,
⇒ Cost = Volume × Rate
⇒ Cost = 2207.33 × 400
⇒ Cost = 882,932
Hence, The cost of the silver solid is ₹ 8,82,932
Answer:
GREAT BRO KEEP IT UP . Thanks
