Math, asked by QWERTYMANGO, 11 months ago

if the total length of a regular triangular prism is 36, and the height is 6, what is the surface area


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Answers

Answered by soodarpit425
1

The base and top are parallel and congruent.

2) Each face, other than base and top, is a parallelogram. Such face is called a Lateral face.

3) The base has one edge common with every lateral face. The top has one edge common with every lateral face.

4) A common edge of two adjacent side faces is called the height of the prism.

Surface Area of Prism (triangular) :

It consists of two parts : 1) Lateral surface area which is the sum of areas of all lateral faces and 2) The area of base and the top.

Lateral faces of right prism is rectangular.

Area of rectangle = length x width = l x w

Base is triangular so either use 1) Area = ½ x base x height or if the height is not given then use Heron’s formula.

Area of faces = Lateral area = Perimeter (P) x Height (h) = ph

Total surface area = 2 x Area of triangle + ph

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Some solved examples on Surface Area of Prism

1) The base of a triangular prism is ΔABC, where AB = 3 cm, BC = 4 cm and ∠B = 90. If the height of the prism is 10 cm. Find 1) Lateral surface area .

2) Total surface area.

Solution :

As ∠B = 90, so by Pythagorean theorem in ΔABC,

C 2 = a 2 + b 2

= 3 2 + 4 2

= 9 + 16

C 2 = 25

C = AC = 5 cm.

Perimeter of Δ ABC = AB + BC + AC = 3 + 4 + 5 = 12 cm

∴ Area of Δ ABC = ½ x 3 x 4 = 6 cm 2

Lateral surface area = ph = 12 x 10 = 120 cm 2

Total surface area = 2 x area of triangle + ph

⇒ = 2 x 6 + 120

⇒ = 12 +120

∴ Total surface area = 132 cm 2 .

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2) The base of a triangular prism is an equilateral triangle of side 6 cm. Its height is 8 cm. Find 1) Lateral surface area 2) Total surface area of the prism.

Solution :

Perimeter of ΔABC = p = 3 x 6 = 18 cm

Area of ΔABC =

Answered by kevalchaudhary651
0

Answer:

hope you got answer

Step-by-step explanation:

The base of a triangular prism is an equilateral triangle of side 6 cm. Its height is 8 cm. Find 1) Lateral surface area 2) Total surface ...

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