If the total number of atoms per unit cell in a hcp structure and a bcc structure get halved , then ratio of % voids in hcp and bcc structures is
1) 34/27
2) 21/22
3) 22/21
4) 37/34
Answers
Answered by
49
answer : option (2) 21/22
explanation : we know, in hexagonal close packed structure (hcp) ; atoms occupy 74% and 28% empty space(voids).
and in body centered cubic structure(bcc) ; atoms occupy 68% and 32% empty space(voids)
now, if If the total number of atoms per unit cell in a hcp structure and a bcc structure get halved.
atoms occupy in hcp = 74/2 = 37%
and voids = (100 - 37) = 63%
atoms occupy in bcc = 68/2 = 34%
and voids = (100 - 34) = 66%
so, ratio of their voids = 63%/66% = 21/22
hence, option (2) is correct choice.
Answered by
7
your correct option is 2
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