If the total of four consecutive numbers is 40, then find the numbers
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Let the 4 consecutive odd numbers be x−3,x−3,x−1,x−1, x+1,x+1, and x+3.x+3. Then,
(x−3)+(x−1)+(x+1)+(x+3)=40(x−3)+(x−1)+(x+1)+(x+3)=40
This equation simplifies to 4x=40,4x=40, so x=10,x=10, and the four numbers are 7,7, 9,9, 11,11, and 13.
(x−3)+(x−1)+(x+1)+(x+3)=40(x−3)+(x−1)+(x+1)+(x+3)=40
This equation simplifies to 4x=40,4x=40, so x=10,x=10, and the four numbers are 7,7, 9,9, 11,11, and 13.
Thank you!!!!!!
wlcm
Your Answer is wrong because the sum is not 40
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