Question

If the total of four consecutive odd numbers is 40, then the smallest no is

Answer 1

Answer:

Let the 4 consecutive odd numbers be [math]x-3,[/math] [math]x-1,[/math] [math]x+1,[/math] and [math]x+3.[/math] Then,

[math]\qquad (x-3)+(x-1)+(x+1)+(x+3)=40[/math]

This equation simplifies to [math]4x=40,[/math] so [math]x=10,[/math] and the four numbers are [math]7,[/math] [math]9,[/math] [math]11,[/math] and [math]13.[/math]

The second number in the sequence is [math]\boxed{~9_{_{~}}^{^{^{~}}}}[/math]