Question

if the total surface area of a solid right cylinder is 880 sq.cm and it's radius is 10cm,find it's curved surface area.(take pi= 22 / 7)​

Answer 1

Answer:

Let r and h be the radius and height of the solid right circular cylinder respectively.

Let S be the total surface area of the solid right circular cylinder.

Given that r=10cm and S=880cm²

Now, S=880 ⇒2πr[h+r]

$2 \times \frac{22}{7 } \times 7 \times 10( h + 10) = 880$

$\implies \: h + 10 = \frac{880 \times 7}{2 \times 22 \times 10}$

$⇒ h+10=14$

Thus, the height of the cylinder, h=4cm

Now, the curved surface area, CSA is

$2\pi \: rh = 2 \times \frac{22}{7} \times 10 \times 4 = \frac{1760}{7}$

Thus, the curved surface area of the

cylinder

=$251 \frac{3}{7} \textsf{sq.cm}$

Answer 2

Answer:

Answer:

Let r and h be the radius and height of the solid right circular cylinder respectively.

Let S be the total surface area of the solid right circular cylinder.

Given that r=10cm and S=880cm²

Now, S=880 ⇒2πr[h+r]

2 \times \frac{22}{7 } \times 7 \times 10( h + 10) = 8802×

7

22

×7×10(h+10)=880

\implies \: h + 10 = \frac{880 \times 7}{2 \times 22 \times 10}⟹h+10=

2×22×10

880×7

⇒ h+10=14⇒ h+10=14

Thus, the height of the cylinder, h=4cm

Now, the curved surface area, CSA is

2\pi \: rh = 2 \times \frac{22}{7} \times 10 \times 4 = \frac{1760}{7}2πrh=2×

7

22

×10×4=

7

1760

Thus, the curved surface area of the

cylinder

=251 \frac{3}{7} \textsf{sq.cm}251

7

3

sq.cm