Question

If the total volume of a simple cubic unit cell is 6.817×10-23 cm3

, what is the volume occupied by particles in unit

cell?​

Answer 1

Answer:

a^3=total volume of unit cell

pie×a^3/6 = volume occupied by particle in unit cell

therefore,

3.14×6.817×10^-23/6

=21.405×10^-23/6

=3.5675×10^-23

~3.57×10^-23

Answer 2

The volume occupied by particles in unit cell is approximately 3.57 × 10⁻²³ cm³

Given : The total volume of a simple cubic unit cell is 6.817×10⁻²³ cm³.

To find : The volume occupied by particles in unit cell.

Solution :

We can simply solve this numerical problem by using the following process. (our goal is to calculate the volume occupied by particles in unit cell)

Now, the volume occupied by particles in unit cell is :

= (π × total volume)/6

= (3.14 × 6.817 × 10⁻²³)/6

= 3.57 × 10⁻²³ cm³ (approx.)

(This will be considered as the final result.)

Hence, the volume occupied by particles in unit cell is approximately 3.57 × 10⁻²³ cm³

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