Chemistry, asked by singhsamz6754, 3 months ago

If the total volume of a simple cubic unit cell is 6.817×10-23 cm3 what is the volume occupied by particles in unit cell

Answers

Answered by amarnathroy64
0

Answer:

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Answered by abhi178
3

Given info : The total volume of a simple cubic unit cell is 6.817 × 10¯²³ cm³.

To find : the volume occupied by particles in unit cell is...

solution : in a simple cubic unit cell,

edge length of unit cell = 2 × radius of each particle.

⇒a = 2r

⇒r = (a/2)

now volume of unit cell = a³ = 6.817 × 10¯²³ cm³ ....(1)

so volume occupied by particles in unit cell = no of particles in unit cell × volume of each particle

= (8 × 1/8) × 4/3 πr³

[ particles are located at corner of a simple unit cell, but each corner is shared by eight unit cell so sharing of particle for each unit cell is 1/8 and also there are eight corner in a cube so total particles = 8 × 1/8]

= 4/3 π (a/2)³

= πa³/6

= (3.14 × 6.817 × 10¯²³)/6 [ from eq (1) ]

= 3.57 × 10¯²³

Therefore volume occupied by particles in the unit cell is 3.57 × 10¯²³ cm³

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