Math, asked by yashraghuvanshi8349, 10 months ago

if the triangle ABC is right angled at C then find the value of sec (A + B) ​

Answers

Answered by reenasalil5
8

Answer:

A+B+C=90 (angle sum property of triangle)

A+B=90 (C=90)

⇒Sec(A+B)=sec(90)

sec(A+B)=not defined

Step-by-step explanation:

Answered by anweshpawar15
1

If C=90 then A+B=90 ( angle sum property of triangle)

sec(A+B)=sec90=which is not defined so

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