If the TSA of a right circular cylinder is 441 and CSA is 1/3 of TSA then what is the volume of the cylinder
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tsa=441 then csa=441/3=147
tsa=2πr^2+2πrh=441
tsa=2πr^2+147=441
then fINd r and h and last vOLume
tsa=2πr^2+2πrh=441
tsa=2πr^2+147=441
then fINd r and h and last vOLume
alka20gupta:
I have already reached this step but not able to solve further. Please tell that further what are we required to do
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