If the TSA of a sphere is 5544 cmsq find the dieter of it
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TSA of sphere = 4πr^2
5544 = 4*22/7*r^2
r^2 = 5544*7/88
r^2 = 4851 cm
r = 69.64 cm
d = 139.28 cm
I hope it will help u
Answered by
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TSA of sphere is 4πr^2
4×22/7×r^2 =5544
5544×7/22×4=18.9/4=r2
r2=4.72
r=2.17
d= 2r
d=2×2.17
d=4.34
hope u will find it helpful
4×22/7×r^2 =5544
5544×7/22×4=18.9/4=r2
r2=4.72
r=2.17
d= 2r
d=2×2.17
d=4.34
hope u will find it helpful
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