if the two angles a and b are complementary angles then prove that 1+ tan a/ tan b = tan ²a × sec ² b
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Step-by-step explanation:
Answer
Given A,B are complementary angles
⟹A+B=90
∘
sinAcosB+cosAsinB−tanAtanB+sec
2
A−cot
2
B
=(sinAcosB+cosAsinB)−tanAtan(90
∘
−A)+sec
2
A−cot
2
(90
∘
−A)
=sin(A+B)−tanAcotA+sec
2
A−tan
2
A=sin90
∘
−1+1=1
satyaprakashverma03:
I can't understand plz can you do it in a paper
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