if the two cubes have their volume in the ratio 1:27 then it ratio of the surface area
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Answered by
5
hey friend here is your sollution
let the radius of both cube be R and r respectively.
Atq.. R³/r³ = 1/27
R/r = 1/3
r = 3R
ratio of surface area = 6×3r/ 6×r
= 3/1
= 3:1 ans
let the radius of both cube be R and r respectively.
Atq.. R³/r³ = 1/27
R/r = 1/3
r = 3R
ratio of surface area = 6×3r/ 6×r
= 3/1
= 3:1 ans
pranavkoli533:
hi
Answered by
8
Hey let the side of biggest cube be x
now the volume will be x^3 & their ratio is 1/27
let the smallest cube be Y then,(Y/x)^3 =1/27,now X=3Y, surface are = 6a^2, now ratio of surface area= 6y^2/6x^2=y^2/x^2=y^2/(3y)^2=1/9
ans=1/9
now the volume will be x^3 & their ratio is 1/27
let the smallest cube be Y then,(Y/x)^3 =1/27,now X=3Y, surface are = 6a^2, now ratio of surface area= 6y^2/6x^2=y^2/x^2=y^2/(3y)^2=1/9
ans=1/9
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