Question

If the two seconds later, how far does the stone go from its point of release? explain? a. 10.4 m b. 5.8 m c. 6.7 m d. 8.8 m

Answer 1

Answer:

)

A

80m

B

100m

C

60m

D

40m

EASY

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ANSWER

v=u+at or v=9.8t

t=

10

30

=3.0s is the time at which stone will reach 30 m/s velocity

First stone will reach s=ut+(1/2)at

2

so s

1

=1/2×10×9m

s

1

=45m

(initial velocity = u = 0)

second stone was dropped after 2sec, so time for itt

1

=3.0−2.0s=1.0s

s

2

=1/2×10×1

2

=5.0m

so distance between two stones

D=45.0−5.0=40.400m

Explanation:

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