Question

If the two zeroes of the quadratic polynomial 7x^2-15x-k are reciprocal of each other then the value of k is?

Answer 1

Answer:

HERE YOUR ANSWER

Step-by-step explanation:

Product of zeroes =alpha×1 by alpha =c by a _ 1 equation

And c by a= -k by 7

Now put c by a in equation 1

Then we get k =-7

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Answer 2

Answer:

value of k is -7

Step-by-step explanation:

let p(x) be $7x^{2} -15x-k=0$

on comparing p(x) with ax²+bx+c , we get

a = 7, b = -15 , c = -k

let the zeroes be α and β

according to the question

β= $\frac{1}{a}$

we know that

αβ= $\frac{c}{a}$

⇒α × $\frac{1}{\alpha }$ = $\frac{-k}{7}$

⇒ 1= $\frac{-k}{7}$

⇒-k=7

⇒k= -7