If the two zeros of polynomial x³+7x²-2x-14 are √2 and -√2 then its third zeros is....
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Answered by
1
Answer:
-7
Step-by-step explanation:
The sum of the roots of a cubic
ax³ + bx² + cx + d
is -b/a.
The cubic x³ + 7x² - 2x - 14 corresponds to a=1 and b=7, so the sum of the roots of this cubic is -b/a = -7.
Given that two of the roots are √2 and -√2, the third root c then satisfies
c + √2 - √2 = -7 ⇒ c = -7
Answered by
3
Answer:
Fine
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