Question

If the uncertainty in momentum of an electron is 2.63*10/25Kgm/s, calculate the uncertainty in it's position

Answer 1

According to Heisenberg's uncertainty principle,

ΔxΔp ≥ h/4π

Where Δx&Δp are the uncertainty in position and momentum respectively and h is Planck’s Constant.

given delta(p) = 2.6 × 10^25 Kgm/s

now

delta(x) = h/ 4 × pi × delta(p)

where

h = 6.6 × 10 to the power minus 34

pi = 3.14