If the valency of iodide is 2 why is the formula of lead iodide is PbI2
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Lead iodide (PbI2)
Valency of Lead - 2
Valency of Iodine - 1
On crossing, we get Pb × 1 and I × 2
i.e. PbI2.
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Answer:
Actually iodide is I^- and has valency of 1
Explanation:
Its valency is one bcos it is a halogen and needs nly one elcetron.Pb has valency of 2.
So using crisscross method we get PbI2
Pb2+ + 2I- ----->PbI2
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