Question

if the value of(-1) n+(1) ²n+(-1) ²n+1+(-1)⁴n+² when n is any positive odd integer​

Answer 1

Answer:

I think this is your Question

{(-1)^n }+ {(1)^2n + 1 }+{ (-1)^4n + 1}

Step-by-step explanation:

Let x be {(-1)^n }+ {(1)^2n + 1 }+{ (-1)^4n + 1}

(-1)^n = (-1)

(-1)^2n = 1

{(-1)^2n+1} = {(-1)^2n}×(-1) = (-1)

{(-1)^4n+1} = {(-1)^4n}×(-1) = (-1)

x = -1 + 1 - 1 - 1 = (-2)

Hope It Helps

Answer 2

Answer:

Let x=(−1)

n

+(−1)

2n

+(−1)

2n+1

+(−1)

4n+1

where n is odd.

(−1)

n

=−1

(−1)

2n

=1

(−1)

2n+1

=(−1)

2n

.(−1)=−1

(−1)

4n+1

=(−1)

4n

(−1)=−1

∴x=−1+1−1−1=−2