if the value of (a^3-b^3/a^3+b^3) when a=7 and b =2 is 335/p, then p is 321
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0
Answer:
The correct option is B False
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
Putting the values of
a
and
b
, we get the value of
p
as
351
.
Alternatively, we can observe that since
a
and
b
are positive, so the denominator has to be greater than the numerator. Thus,
a
3
+
b
3
will be greater than
a
3
−
b
3
.
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