if the value of (a+b) and ab are 12 and 32 respectively, find the value of a^2+b^2 and (a-b) ^2.
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Answer:
given,
a+b= 12
ab=32
=> (a+b)^2=a^2+b^2+2about
let a^2+b^2=x
=> 144=x+2×32
=>a^2+b^2=80
=>(a-b)^2=x-2ab
=> (a-b)^2= 16
=> a-b=4---(1)equation
=> a+b=12------(2) equation
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=> 2a=16(add both the equations)
=> a=8,b=12-a= 4
Step-by-step explanation:
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