if the value of a+b+c=10and ab+bc+can=8 then find a²+b²+c²
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84 is answer.
⇒ a + b + c = 10
Square on both sides:
⇒ (a + b + c)² = 10²
⇒ a² + b² + c² + 2(ab + bc + ca) = 100
⇒ a² + b² + c² + 2(8) = 100
⇒ a² + b² + c² = 100 - 16
⇒ a² + b² + c² = 84
BrainlyPrince007
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Answer:
84
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