if the value of a + b + c is equals to zero then find the value of a3 + b3 + c3
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using a3 + b3 + c3 - 3abc = ( a + b + c ) ( a2 + b2 + c2 - ab - bc - ca )
here if a+b+c = 0 then the answer will be 3abc because in RHS ( a + b + c ) becomes 0(zero) in multiplying the whole becomes 0. and when transposing -3abc it becomes +3abc. so here it becomes
a3 + b3 + c3 = 3abc
hope u r clear wid it!! :D
here if a+b+c = 0 then the answer will be 3abc because in RHS ( a + b + c ) becomes 0(zero) in multiplying the whole becomes 0. and when transposing -3abc it becomes +3abc. so here it becomes
a3 + b3 + c3 = 3abc
hope u r clear wid it!! :D
harsh579145:
how prove that please
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