If the value of acceleration due to gravity on the surface of the earth is 9.8 m/s2, find the mean value of density of earth. Given R = 6400 km and G = 6.67 x 10–11 SI unit
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Answer:
11th
Physics
Gravitation
Acceleration due to Gravity
the value of g at the surfa...
PHYSICS
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Asked on December 26, 2019 by
Shaik Sethi
the value of g at the surface of the earth is 9.8m/s
2
. then the value of g at the place 480km above the surface of the earth will be nearly? (Radius of the earth is 6400km )
MEDIUM
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ANSWER
M= mass of earth
R= radius of earth =6400km=6.4×10
6
m
g
1
= acceleration due to gravity on the surface of earth =9.8m/s
2
h= height above the surface of earth 480km=0.480×10
6
m
g
2
= acceleration due to gravity above the surface of earth=?
acceleration due to gravity on the surface is given
g
1
=
R
2
GM
----------------------------(1)
acceleration due to gravity above the surface is given:
g
2
=
(R+h)
2
GM
------------------(2)
g
1
g
2
=
R
2
GM
(R+h)
2
GM
g
1
g
2
=
(R+h)
2
R
2
9.8
g
2
=
((6.4×10
6
)+(0.480×10
6
))
2
(6.4×10
6
)
2
g
2
=8.5m/s
2
.