Question

If the value of C.F.S.E. for “Ni” is del0 then for Pd it should be​
a) 1.1 del0
b) 0.5 del0
c) 1.5 del0
d) 2 del0

Answer 1

Hey dear,

● Answer -
(c) 1.5∆°

● Explaination -
- Value of CFSE increases by 50% as we go from 3d to 4d period in same group.
- Nickel is positioned as 10th element in 3d series while Palladium is 10th element in 4d series.
- Therefore, CFSE for Pd will be 50% more than that for Ni.
CFSE(Pd) = (100+50)/100 × ∆° = 1.5 ∆°

Hope this helps you...