if the value of criterion of quadratic equation xcube-3x-k=0 is 1 , then k is ?
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Given
Quadratic Equation ;
x³ - 3x - k = 0
Given that ;
x = 1
( 1 )³ - 3 ( 1 ) - k = 0
1 - 3 - k = 0
- k = 2
k = -2
Or
Discriminant ( ∆ ) = b² - 4ac
a = 1 ; b = -3 ; c = - k
∆ = ( -3 )² - 4 ( 1 ) ( - k )
∆ = 9 + 4k
4k = -9
k = - 9 / 4
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