Question

if the value of determinant is 3√6 -4√2 and 5√3 x is 26√6 find the value of x​

Answer 1

$\textbf{Given:}$

$\left|\begin{array}{cc}3\sqrt{6}&-4\sqrt{2}\\5\sqrt{3}&x\end{array}\right|=26\sqrt{6}$

$\textbf{To find:}$

$\text{The value of x}$

$\text{Consider}$

$\left|\begin{array}{cc}3\sqrt{6}&-4\sqrt{2}\\5\sqrt{3}&x\end{array}\right|=26\sqrt{6}$

$\text{Expanding, we get}$

$3x\sqrt{6}+20\sqrt{6}=26\sqrt{6}$

$\implies\,3x\sqrt{6}=26\sqrt{6}-20\sqrt{6}$

$\implies\,3x\sqrt{6}=6\sqrt{6}$

$\implies\,3x=6$

$\implies\boxed{\bf\,x=2}$

$\therefore\textbf{The value of x is 2}$

Find more:

The sum of the real roots of the equation | x 6 1 |

| 2 3x (x - 3)| = 0 | 3 2x (x = 2)|

is equal to (A) -4 (B) 0

(C) 6 (D) 1

https://brainly.in/question/16074720

Answer 2

Step-by-step explanation:

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