Question

If the value of discriminant of a quadratic equation Kxsq - 4x -4 =0 is 64 then k is

Answer 1

Answer:

k = 3

Step-by-step explanation:

$p(x)=kx^2-4x-4=0 \\ \\ \\ a = k\ \ \ ; \ \ \ b = -4\ \ \ ; \ \ \ c = -4$

$b^2-4ac=64 \\ \\ (-4)^2-(4\times k \times -4)=64 \\ \\ 16-(-16k)=64 \\ \\ 16+16k=64 \\ \\ 16(k+1)=64 \\ \\ k+1=\frac{64}{16} \\ \\ k+1=4 \\ \\ k=4-1 \\ \\ k=\bold{3}$

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