Question

If the value of e vector =6i cap +3j cap+4k cap , find the electric flux through a surface area 20 unit lying in yz-plane

Answer 1

Given:

Value of E vector is 6i + 3j + 4k .

Surface area is 20 square units in the Y-Z plane.

To find:

Electrostatic flux passing through the given area.

Calculation:

Since the area plane is located in the Y-Z plane, we can say that the area vector is along the x axis.

$\therefore \: \phi = \vec E \: . \: d \vec s$

$= > \: \phi = (6 \hat i + 3 \hat j + 4 \hat k)\: . (\: 20 \hat i)$

$= > \: \phi = (6\times20) + 0 + 0$

$= > \: \phi = 120 \: units$

So , net flux is 120 units.

Important things to note:

• Dot product between perpendicular vectors is zero.

• Dot product between parallel unit vectors is 1.