If the value of excluded volume of O, is 5.2 cm3
then its critical volume will be
(1) 1.73 cm3
(2) 15.6 cm3
(3) 5.2 cm
(4) 10.6 cm3
Answers
Answered by
9
The correct option is 2 which is 15.6cm^3
Explanation:
so the problem can be solved by using formula Vc(critical volume)=3b(excluded volume)
Vc=3*5.2=15.6
simple as it is
hope it's helpful n u got it
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