Math, asked by aneesha1906, 22 days ago

If the value of given polynomial is 13 for a=2,
then
find the value of n. p(a)= a² + 2a+ n​

Answers

Answered by apm43
0

p(a) =  {a}^{2}  + 2a + n \\ p(2) =  {2}^{2}  + 2 \times 2 + n = 13 \\ 8 + n = 13 \\ n = 5

Hope my answer will help you

Answered by AtikRehan786
0

Step-by-step explanation:

We know that equation ax2+bx+c=0

Then sum of roots =a/−b and product of roots=a/c

Let the other zero be α

Therefore, the other zero is α/1

Now, α×α1=a2−96a

=》a×1/a=6a/a sq-9

=>a sq+9−6a=0

=>a sq−6a+9=0

=>a sq−3a−3a+9=0

=>a(a−3)−3(a−3)=0

=>(a−3)(a−3)=0

=>a=3 and a=3

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