If the value of given polynomial is 13 for a=2,
then
find the value of n. p(a)= a² + 2a+ n
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Step-by-step explanation:
We know that equation ax2+bx+c=0
Then sum of roots =a/−b and product of roots=a/c
Let the other zero be α
Therefore, the other zero is α/1
Now, α×α1=a2−96a
=》a×1/a=6a/a sq-9
=>a sq+9−6a=0
=>a sq−6a+9=0
=>a sq−3a−3a+9=0
=>a(a−3)−3(a−3)=0
=>(a−3)(a−3)=0
=>a=3 and a=3
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