If the value of n(n²-1) is six time value of ∑d² then what is the value of r??
Answers
Given : the value of n(n²-1) is six time value of ∑d²
To Find : the value of r
Solution:
rank correlation coefficient r = 1 - 6 ∑ (di)² / (n(n² - 1))
n = numbers
∑ (di)² = sum of squares of the differences in ranks
r = rank correlation coefficient
Now its given that n(n²-1) is six time value of ∑d²
=> n(n²-1) = 6 ∑d²
Substituting value in formula
r = 1 - 6 ∑ (di)² / (n(n² - 1))
=> r = 1 - 6 ∑ (di)² / 6 ∑d²
=> r = 1 - 1
=> r = 0
value of r is 0
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