if the value of quadritic polynomial p(x) is 0 only at x=-1 and p(-2)=2,then the value of p(2) is
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Hey! Friend,
☺️Here is ur answer☺️
a,b,c are in AP so a+c=2b
P(x)=ax^2+bx +c=0
x^2+(b/a)x+c/a=0
Sum of the roots = -b/a
Product is =c/a
Adding we get c/a-(a+c)/2a=(2c-a-c)/2a=c/2a-1/2
HOPE IT HELPS YOU.
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☺️Here is ur answer☺️
a,b,c are in AP so a+c=2b
P(x)=ax^2+bx +c=0
x^2+(b/a)x+c/a=0
Sum of the roots = -b/a
Product is =c/a
Adding we get c/a-(a+c)/2a=(2c-a-c)/2a=c/2a-1/2
HOPE IT HELPS YOU.
MARK ME BRAINLIEST.
SarthakDoshi:
its a completely different answer
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here is your answer
in this pic
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