if the value of sin(x+y)sin(x-y)+ sin(y+z)sin(y-z)+sin(z+x)sin(z-x)
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Answer:
sin(x+y)sin(x-y)+sin(y+z)sin(y-z)+sin(z+x)sin(z-x)
=sin²x-sin²y+sin²y-sin²z+sin²z-sin²x
=0
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