Math, asked by arnavdeshpande87, 2 months ago

If the value of the determinant is (image) is
26 \sqrt{6}
find the value of x

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Answers

Answered by Anonymous
1

Answer:

| 3√6 -4√2 | = 26√6

| 5√3 x l

» | 3√6 -4√2 | = 26√6

| 5√3 x l

» (3√6x + 20√6) = 26√6

» 3x + 20 = 26

» 3x = 6

» x = 2

Therefore, the value of x is 2.

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