Physics, asked by sheetalsaumya, 1 year ago

If the value of two temperatures are
T1 = (40.3 + 0.1)°C and T2 = (70.2 + 0.2)°C, then the
value of (2T1 + 2T2) upto proper error limit is
(1) (221.0 + 0.1)°C (2) (221.0 + 0.6)°C
(3) (221.0 - 0.2)°C (4) (221.0 + 0.3)°C​

Answers

Answered by AishRanglani
1

2option is the answer

Explanation:

multiply bolth of them by 2then add ...

Answered by handgunmaine
2

Value of 2(T_1+T_2) upto proper error limit is ( 221+0.6)^{\circ}C .

Given :

T_1 = (40.3 + 0.1)^{\circ}C and T_2 = (70.2 + 0.2)^{\circ}C .

We need to find the value of 2(T_1+T_2)  upto proper error limit is .

So , value of T_1+T_2 is 40.3 + 70.2 i.e 110.5^{\circ}C .

Therefore , value of 2(T_1+T_2) is 221^{\circ}C .

Now , total error is :

2( 0.1+0.2)^{\circ}C

0.6^{\circ}C .

Therefore , value of 2(T_1+T_2) upto proper error limit is :

( 221+0.6)^{\circ}C

Hence , this is the required solution .

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