Question

If the value of x
$x = \sqrt{2}$
$y = \sqrt{3}$
Then solve ,
$x = 4y$
​

Answer 1

Value of x and y,

$x = \sqrt{2}$

$y = \sqrt{3}$

Given equation,

$x = 4y$

putting the value in the equation,we get

$\sqrt{2} = 4\sqrt{3}$

$\Rightarrow 4\sqrt{3} - \sqrt{2}$

or.....

$2 = (4\sqrt{3})^{2}$

$2 = 16 × 3$

$2 = 48$

$\Rightarrow 48 - 2$

$\Rightarrow 46$