Question

if the value of x-y= 7 and xy=9 then the value of 4x^2+4y^2 is?​

Answer 1

Answer:

268

Step-by-step explanation:

4(x^2+4y^2)

= 4(x^2+y^2-2xy+2xy) (Add and subtract 2xy)

= 4[(x-y)^2+2xy] (As x^2+y^2-2xy=(x-y)^2)

= 4[7^2+2(9)] (as x-y=7, xy=9)

= 4(49+18)

= 4(67)

= 268

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