If the values of k for quadratic equation 2x^2-kx+4 has equal roots are
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Given:-
- Quadratic equation 2x² - kx + 4 has real roots.
To find:-
- Value of k
Solution:-
Compare the given equation with the standard quadratic equation ax² + bx + c = 0
we get, a = 2 , b = -k and c = 4
The given equation has equal roots so,
the discriminant must be zero.
D = b² - 4ac = 0
= (-k)² - 4 × 2 × k = 0
= k² - 8k = 0
= k(k - 8) = 0
= k - 8 = 0
= k = 8
★ Hence, the required value of k are 0 and 8.
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