Question

If the variance of 1, 2, 2, 3 is λλ, then the value of log2λlog2λ is

Answer 1

Such a tough question

Answer 2

Answer: The value of log2λlog2λ is 0.172.

To find the value of log2λ, we first need to calculate the mean of the given numbers:

mean = (1+2+2+3)/4 = 2

Next, we need to calculate the variance, which is the average of the squared deviations from the mean:

variance = ((1-2)^2 + (2-2)^2 + (2-2)^2 + (3-2)^2)/4 = 0.75

Since the variance is given to be λ, we have:

λ = 0.75

Taking the logarithm on both sides,

log2λ = log2(0.75)

Using base formula,

log2(0.75) = log10(0.75)/log10(2) ≈ -0.415

Therefore, log2λ ≈ -0.415, and:

log2λlog2λ = (-0.415) * (-0.415) = 0.172

Learn more about variance here

https://brainly.in/question/19980211

Learn more about mean here

https://brainly.com/question/1136789

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