If the vector A^=0.4Ci^+0.6j^ represent a unit vector then the value of C is
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Answer: C=±2
Given vector A is a unit vector, so it's magnitude should be equal to 1.
|A|=√(0.4C)² + (0.6)² =1
⇒0.16C²+0.36=1
⇒0.16C²=1-0.36=0.64
⇒C²=0.64÷0.16=4
⇒C=±2
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