If the vector A=3i+4j-5k and B=5i-3j+4k then find the angle between the vectors A+B and A-B......
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A+B=8i +j -k
A-B= -2i +7j -9k
let A+B = C
and A - B = D
then cosine of angle between 2 vectors is given by
cos(theta)=A·B/|A||B|
A·B= 0
hence cos(theta)=0
theta = 90°
A-B= -2i +7j -9k
let A+B = C
and A - B = D
then cosine of angle between 2 vectors is given by
cos(theta)=A·B/|A||B|
A·B= 0
hence cos(theta)=0
theta = 90°
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