If the vectors 2i-3j+ 4k,i +2j-k and xi Nj+ 2k are coplanar then x-
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Answer:
hey mate here is your answer...
Step-by-step explanation:
i+3j−2k,2i−j+4k and 3i+2j+pk are coplanar
⇒
∣
∣
∣
∣
∣
∣
∣
∣
1
2
3
3
−1
2
−2
4
p
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒(−p−8)−3(2p−12)−14=−7p+14=0
∴p=2
Hence, option B.
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