Question

If the vectors ab 3i + 4k and ac = 5i 2j + 4k are the sides of a triangle abc, then the length of the median through a is

Answer 1

Answer:

Position vector of AD

= 2

(3+5)i+(5−5)j+(4+2)k

AD= 2

8i+6k =4i+3k

∴ Length of median =∣AD∣=

16+9 =5 units.

Answer 2

Answer:

position vector of AD = 2

AB+AC=(3+5)i+(5-5)j+(4+2)k

AB+AC=(8)i+(0)j+(6)k

AB+AC=8i+6k

AD=2

8i+6k=4i+3k

therefore length of median = |AD|=16+9=5units

|AD|=5units

Step-by-step explanation:

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