Question

If the velocity is V= 2i^+ t^2j^-9k^, then the magnitude of acceleration at t=0.5 s is

Answer 1

Answer:

Velocity when t=2s is v

2

=10+2×4=18m/s

Velocity when t=5s is v

5

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=

Δt

Δv

=

3s

42m/s

=14m/s

2