Question

if the velocity is v=2i+t²j-9k vector then the magnitude of acceleration at the equal to 0.5 seconds

Answer 1

it's very easy.
v=2i+t²j-9k
differentiating both sides w.r.t. t
dv/dt=2t
we know that:
a= dv/dt
a=2t
at t=0.5 seconds
a=2×0.5=1m/s
please mark me brainliest

Answer 2

Answer:

v=2i+t^2 j -9k

t= 0.5s

dv/dt=2t

since , a= dv/dt

a=2t

a=2×0.5

a=1 m/s^2

hope it helps