If the velocity of a body becomes two times its initial velocity, then by how many times will its kinetic energy increase
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Let the initial velocity be v and final velocity be v'.
Then, initial kinetic energy=1/2 mv².
And, final kinetic energy=1/2 mv'²
=1/2 m(2v)²
=1/2 m × 4v²
=4 × 1/2 mv²
=4 × E₁.
∴ The kinetic energy becomes 4 times when velocity is doubled.
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