Question

If the velocity of a body changes from 10 m/s to 22 m/s in 6 seconds. Its acceleration is

Answer 1

Initial velocity = 10 m/s

Final velocity = 22 m/s

Time taken for speeding up = 6 seconds

Thus,

$\tt{Acceleration} = \frac{22 - 10}{6} \\ \\ = > \frac{12}{6} \\ \\ = > 2 \: \: \bf {ms}^{ - 2}$

Answer 2

Explanation:

initial velocity(u) = 10m/s

final velocity(v) = 22m/s

time(t) = 6 seconds

acceleration(a) = ???

By motion in 1D formula,

v = u+at

or, 22= 10 + a×6

or, 22-10 = a×6

or, 12 = a×6

or, 12÷6 = a

or, a = 2

Therefore, the acceleration is 2m/s^2.

Answer.